Please help asap. Need to know asap
If I react 4.3 g of Zinc with excess Bromine (liquid)
the reaction is
Zn (s)+ Br2 (liquid) --> Zn Br2 = ZnBr2
does this mean that there are TWO molecules of bromine required for every ONE molecule of Zn?
and if the values of heat for the reaction are H= -329 kJ/mol
how much heat is released or absorbed during the reaction?
chemistry reaction equation help please!
- Ocean Breeze
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- Xenon
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Re: chemistry reaction equation help please!
2 atoms of Br and 1 atom of Zn in one molecule of Zinc Bromide
4.3g Zn (atomic wt. = 65.38) = 4.3/65.38 = 0.0658 moles x -329 = -21.64kJ
4.3g Zn (atomic wt. = 65.38) = 4.3/65.38 = 0.0658 moles x -329 = -21.64kJ
Xe, SD, KOPR
- Ocean Breeze
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Re: chemistry reaction equation help please!
Xenon
Thank You
I didnt want to second guess myself at all, I could have been way out.
This was very helpful
R-S
Thank You
I didnt want to second guess myself at all, I could have been way out.
This was very helpful
R-S