![Huh ? :?](./images/smilies/huh.gif)
I have just done titration in order to standardise Na OH.
I used oxalic acid as the standard, at 0.0500 M/L
My Na OH is approx 0.1 M/L. the tect book says that
2Na OH + H2 C2 O4 ---> Na2 C2 O4 +2H20.
These are my averaged results.
20 ml of 0.0500 M/L oxalic acid is neutralised by 10.17 ml of Na OH
From here, how do I get to the molarity of the Na OH from here? and if possible, can you lay out the steps? Cnt remeber what to do about the 2Na OH compared to the single oxalic acid.
Thanks in advance (hopefully!)